A riddle wrapped in a mystery inside a balls-up

Consider #2 on the Mori-Mukai list of rank-3 Fano 3-folds.  This has been giving us some difficulty, which I have now resolved.  We were making a combination of mistakes.  Mori and Mukai describe the variety X as follows.

A member of |L^{\otimes 2} \otimes_{\cO_{\PP^1 \times \PP^1}}  \cO(2,3)| on the \PP^2-bundle \PP(\cO \oplus  \cO(-1,-1)^{\oplus 2}) over \PP^1 \times \PP^1 such that  X \cap Y is irreducible, where L is the tautological line bundle and Y is a member of |L|.

Our first mistake, as Mukai-sensei pointed out in an email to Corti, was using the wrong weight convention for projective bundles.  Mori and Mukai use negative weights, so the ambient \PP^2-bundle F is the toric variety with weight data:
\begin{array}{cccccccc} x_0 & x_1 & y_0 & y_1 & t_0  & t_1 & t_2   &   \\ 1 & 1 & 0 & 0 & 0  & 1  & 1 & \\ 0& 0 & 1 & 1 & 0  & 1  & 1  & \\ 0 & 0 & 0 & 0& 1  &1 & 1  & \end{array}
For later convenience we change basis, expressing F as the toric variety with weight data:
\begin{array}{cccccccc} x_0 & x_1 & y_0 & y_1 &  t_0  & t_1 & t_2   &   \\ 1 & 1 & 0 & 0 & -1   & 0  & 0 & A \\ 0& 0 & 1 & 1 & -1  & 0   & 0  & B \\ 0 & 0 & 0 & 0& 1  &1 & 1   & C  \end{array}
X is a section of |B+2C|.

Our second mistake was failing to accurately account for the fact that although X is Fano, the bundle A+C (which restricts to -K_X on X) is only semi-positive on F.  Thus we are in the situation described in this post and, in the notation defined there, we have:
\begin{cases} F(q) = 1 \\ G(q) = 2q_3+6q_2 q_3 \\ H_1(q) =  \sum_{b>0} {(-1)^{b} \over b} q_2^b = {-\log(1+q_2)} \\ H_2(q) = {-\log(1+q_2)} \\  H_3(q) = \log(1+q_2) \end{cases}
and hence:
\begin{cases} q_1 = {\hat{q}_1 \over 1 - \hat{q}_2} \\ q_2 = {\hat{q_2} \over 1 - \hat{q_2}} \\ q_3 = \hat{q}_3 (1-\hat{q_2}) \end{cases}
Thus the cohomological-degree-zero part of the J-function is:
\exp({-2}\hat{q}_3(1-\hat{q}_2)-6\hat{q}_2 \hat{q}_3)  \sum_{a,b,c\geq 0} \hat{q}_1^a \hat{q}_2^b  \hat{q}_3^c(1-\hat{q}_2)^{c-b-a} {1 \over z^{a+c}} {(b+2c)! \over a!a!b!b!c!c!(c-b-a)!}
and setting \hat{q}_1 = t, \hat{q}_2 = 1, \hat{q}_3 = t, z=1 yields:
\exp(-6t)  \sum_{a,b\geq 0} t^{2a+b} {(2a+3b)! \over a!a!b!b!(a+b)!(a+b)!}
Regularizing this gives:
I_{reg}(t) =1+58 t^2+600 t^3+13182 t^4+247440 t^5+5212300 t^6+111835920 t^7+ \cdots
As Galkin conjectured, this is period sequence 97.

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