Slicing the data

Sergei: I sliced the Minkowski period data as you requested, here.

Update: here is a new version which also contains the Picard ranks.

8 Comments

  1. Tom says:

    Sergei: for \CC P^2 \times \CC P^1 I get N=4, r=9. See period sequence 44.

  2. Tom says:

    OK, not tomorrow. Maybe the next day…

  3. Sergei says:

    Tom: thank you very much, I figured out my disambiguation.
    The problem is the apparent singularities.

    Choose a coordinate W = \frac{1}{t}.
    Choose \omega = e^\frac{2 \pi i}{3} — a root of \omega^2 + \omega + 1 = 0.

    For P^1 there are two singularities: W=2 and W=-2.
    For P^2 there are three singularities: W=3, W = 3 \omega and W= 3 \omega^2.

    In case of P^1 \times P^2 we should have 6 singularities, in coordinate W these are the sums singularities for P^1 and for P^2:
    1=3-2, 5 = 3+2, two roots of a^2+7 a+19 are 3 \omega +2 and 3 \omega^2 +2, two roots of a^2 – a + 7 are 3 \omega -2 and 3 \omega^2 -2.

    In inverse to W coordinate t this should correspond to a product
    (1-t) (1 - 5t) (1 -t +7 t^2) (1 + 7 t + 19 t^2) in front of D^4.

    However the symbol of PF equation is not exactly this degree 6 polynomial, but
    degree 9 polynomial in t:
    107730*t^9 – 211376*t^8 – 50139*t^7 + 156996*t^6 – 20520*t^5 + 16194*t^4 + 1782*t^3 – 448*t^2 – 243*t + 24
    There is an extra factor of 24 - 243 t - 160 t^2 + 160 t^3, solutions of this degree 3 equation are apparent singularities – the monodromies around these points are identities.

    So far I cannot think on an easy cure for these (not involving computing the monodromies).
    However it could be useful to check for the decomposition (over integers) of the PF’s symbol – if the symbol is indecomposable and of high degree (more than 10 in general) then it is certainly suspicious.

    For smooth Fano threefold with (G-invariant) Picard number \rho we expect N to be \rho + 2 and r to be \leq 2 \rho + 2.
    So we expect the symbol to have some factors of degree \leq 2N-2.

  4. Sergey says:

    For Picard ranks, could you please add both maximal and minimal ranks that appear?

    When Fano has a degeneration to (Gorenstein/any) toric variety with Pic=Z ?

  5. Tom says:

    I’ve added a new version containing the Picard ranks.

    Sergei: I grabbed these directly from grdb because I couldn’t get your gp code to work. Did you mean concat rather than matconcat?

    Sorry about the delay — I was on holiday.

  6. Sergey says:

    Tom: sorry, indeed I have alias matconcat=concat for backward compatibility.
    Here are my .gpalias and .gprc files.

    Generally degree deg = (-K_Y)^3 = 2g-2 and Picard rank \rho = \rho(Y) is not enough to determine the smooth Fano Y.
    We need two more invariants:
    b = b(Y) = h^{1,2} (Y) and
    d = d(Y) — discriminant of quadratic form q(A) = -K_Y \cdot A \cdot A on the lattice Pic(Y).

    For STD \rho(Y) = \rho(X) = \rho and number b is given by the formula

    b(Y) = (\rho -1) + (v - f)

    where v and f are numbers of vertices and faces of fan polytope.
    So number b should also be easily derived from grdb data.

    Also for STD d(Y) = d(X).
    However I don’t think there is any way to compute this number essentially simpler than the obvious one used in my script.

    In case of degeneration to non-terminal Gorenstein variety X Picard number \rho may fall down.

    If for some reason Picard number remains the same, then Pic(X) is a sublattice of Pic(Y) of some finite index r. Then
    d(Y) = r^2 d(X),
    but since d(Y) is rarely divisible by a square this happens not so often.

  7. Sergey says:

    Tom, could you please post a new version which contains both Picard ranks and degrees?

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